![]() We only need to check half of the board, as the solutions of the other half would be symmetrical.īut despite these the code is still very slow.Optimizations I have come up with so far: If re.search(expression1, string) or re.search(expression2, string): English version and French version of the peg solitaire board. this is a card gameso it is identified as 'Peg Solitaire'. In England it is known as 'Solitaire' in the U.S. One of the most common configurations is a cross. The goal is to remove all pegs but one by jumping pegs from one side of an occupied peg hole to an empty space, removing the peg which was jumped over. A set of integer variables Mi j t d is de ned to denote the movesto be made from each location(i j) 2 B. In such a model, the constraints de ne the feasible moves and purging, and the objective is to have one single remaining peg in the centre of the board. If board and board and not board:Įxpression1 = '1000+1' #RE for a proven to be unsolvable boardĮxpression2 = '00100' #RE for a proven to be unsolvable board Peg solitaireis a classical puzzle commonly played on a 33-hole cross-shaped board (also known as 'the English board') or a 15-hole triangular board. A game played on a board of a given shape consisting of a number of holes of which all but one are initially filled with pegs. Finding a solution to Peg Solitaire may be formulated as an integer programming model. It uses a single number to represent a position (one bit per place, with 0hole, 1peg) and a bit array for the map of all visited states (indexed by position number). So I was wondering if there are some optimizations I could do or different solution approaches. You can find my solver here /6502/peg-solitaire. ![]() each having a different solution: Standard, Square, European, Asymmetric, Rhombus, German. I have created a brute force algorithm which finds all the possible moves until a valid solution is reached, but it starts taking a very long time to find a solution past n > 20. (PDF) Solving Triangular Peg Solitaire - ResearchGate. The goal of the algorithm I am trying to make is to take an input of n where n > 2 and n is an even number, then for a board of length n, find all the positions for a start state at which a hole can be placed to produce a valid solution. So for a board such as board = there are two available moves. Your available moves at any given position is to move one peg by two positions to the right or to the left if and only if there is a peg between the two position, then once you make that move, replace the middle peg with a hole. The goal of the game is to reach a board state where n-1 elements are holes and 1 element is a peg at any given position. So a starting position can be where 1s represent pegs and 0s represent holes for n = 6 ![]() n-1 elements are pegs (filled) and 1 element is a hole (empty). One solution is to convert board to a 49-bit number by traversing through the entries in each of eight orders corresponding to the eight symmetries, as shown in Figure 6. Peg Solitaire is a game that consists of a board with thirty three holes, each filled with a peg, except for the center hole. You initially start with a 1 dimensional board of length n. First I will explain the rules of peg solitaire (for 1 dimension): ![]()
0 Comments
Leave a Reply. |